Extra Credit (2) Pokemon is a gam has a type (sometimes 2 types, but let's stick to 1 for this problem) and that type is better against certain types, weaker against some types and neutral to...
Extra Credit (2) Pokemon is a gam has a type (sometimes 2 types, but let's stick to 1 for this problem) and that type is better against certain types, weaker against some types and neutral to other types (also has no effect sometimes, but again not here). Let's say that one trainer (player R) brings 2 poke- mon to a battle and another trainer (player C) brings 2 pokemon to the battle. Player R brings a grass type and a water type pokemon and player C brings a rock type and an ice type. Each player chooses one of their pokemon to battle with. Construct the payoff matrix for the game using a 1 for player R win, -1 for a player C win and 0 for a tie. Is the game strictly determined? If not, determine each player's optimized strategy. Either way find the value of the game. The type matchups are as follows: rass beats rock water beats rock ice beats grass water ties with ice e similar to rock-paper-scissors in that each pokemon
Extra Credit (2) Pokemon is a gam has a type (sometimes 2 types, but let's stick to 1 for this problem) and that type is better against certain types, weaker against some types and neutral to other types (also has no effect sometimes, but again not here). Let's say that one trainer (player R) brings 2 poke- mon to a battle and another trainer (player C) brings 2 pokemon to the battle. Player R brings a grass type and a water type pokemon and player C brings a rock type and an ice type. Each player chooses one of their pokemon to battle with. Construct the payoff matrix for the game using a 1 for player R win, -1 for a player C win and 0 for a tie. Is the game strictly determined? If not, determine each player's optimized strategy. Either way find the value of the game. The type matchups are as follows: rass beats rock water beats rock ice beats grass water ties with ice e similar to rock-paper-scissors in that each pokemon