pls show work & do not use l’hopital lim tan(5x) xo In(1 +8x) lim tan(5x) xo In(1 +8x)
solve please now
Evaluate the following limit using Taylor series. 8 tan* *(x) – 8x+x lim x³0 33³ 8 tan (x) – 8x + x2 lim X-0 = (Simplify your answer.) 3x
How do I simplify this fraction, pls show steps
16(48-29-5x+1)*- (4x-2)^(-26 (-6x+1)* (-5x+1)'0
solve d-f
Find the limits and show your work. Use L'Hospital's Rule where appropriate. (a) lim-0 tan 3.0 2.2 1 (b) limu+0+ In(X) (c) limx→ In(x + 3) – In(3x + 2) (d) limz+ x sin(5) (e) lim.+ 22-45 4" +3: (f) limo (#2) (g) lim + (e+ + a)*
Use L'Hospital to determine the following limit. Use exact values. lim (1 + sin 5x)} = 3-0
QUESTION 3 Use the graph to find the limit, if it exists. lim f(x) =[a] x + 1 3(x) co . - 2 - -1 -27 QUESTION 4 Use the graph to find the limit, if it exists. 4 lim XO 1 2+ex =[a] 2 - 2 QUESTION 5 Use the graph to find the limit, if it exists. lim tan X = [a] XT/2 Fla T 1
40 Show the following results. 1-e2 (e) lim(2+3-12)tan(/4) (24.3)-4/ 2 (a) lim -+0 isin(3r) エ→2 3 (f) lim(cos x)In | = 1 エ→0 1+ tanz1/sin z 1+ tanh r (b) lim = 1 -+0 nT nT (g) lim cos no0 +sin 6n+1 (c) lim (sin r)1/(2r-) - 1 エ→/2 = e 3n+1 2 + sin r 1 (h) lim 0. (d) lim エー→0 1 In (1 - V-1) - . 2 In(cos x) r+1+
40 Show the following results. 1-e2...
(Hint: think of tan as a fraction!) lim (1 - .) tan 7. Suppose a function f(x) satisfies f'(x) < 0 and f(x) > 0 for all x 20. > 0 for all x > 0. Consider the function F(x) := ["s(t) dt whose domain is 0,00). Is F(x) an increasing or decreasing function
verify the following 1) tan x+cot y= sin(x+y)/cos x sin y 2) tan 5x + cot 5x = 2 csc 10x
show work
1) Find the limit if it exists. x? - 7x +10 x² + x-30 a) lim tan x b) lim c) lim tan x In x
#1. Using the definition of big-O, prove that f(x) = 5x^4+x^3+8x-2 . Show all work. #2. void bubbleSort(Student myClass[], int size) { int pass = 0; // counts each pass of the sort bool done = false; // whether sorted or not // each pass puts one element into its sorted position, // smallest value bubbles to the top of the array while (!done) { done = true; // possibly sorted // compare consecutive elements, swap if out of order...