Question

(1 point) The following Exercise is based on summary statistics rather than raw data. This information is typically all that is presented in published reports. You can calculate inference procedures by hand from the summaries. Use the conservative Option 2 (degrees of freedom the smaller of ni1 and n2 - 1 for two-sample t confidence intervals and P-values. You must trust that the authors understood the conditions for inference and verified that they apply. This isn't always true.) Equip male and female students with a small device that secretly records sound for a random 30 seconds during each 12.5-minute period over two days. Count the words each subject speaks during each recording period, and from this, estimate how many words per day each subject speaks. The published report includes a table summarizing six such studies. Here are two of the six: Sample Size Estimated Average (SD) of Words Spoken per Day Number Women Men Women Men 155 55 15089 (7659)16574 (9118) 2 26 22 16352 (7796) 12815 (8379) Readers are expected to understand this to mean, for example, the 55 women in the first study had x-15089 and S-7659 It is commonly thought that women talk more than men. Does either of the two samples support this idea? For each study: (a) State the alternative hypothesis in terms of the population mean number of words spoken per day for men μΜ) and for women 41F). If necessary, use != to represent Study 1: M Study 2: μΜ (b) Find the two-sample t statistic to test HF -M Study 1: Study 2: (c) What degrees of freedom does Option 2 use to get a conservative P-value? Study 1 Study 2: (d) Compare your value of t with the critical values in Table C. What can you say about the P- value of the test? Study 1: P- value> Study 2: S P- value

Answer 1

B) Nul, hypot유e.es: JAn>Mp Alternative hupoffen: μΜ4f b) tudy 15089) Sg 1659 The test stot sha 2 167u IS089 レナ169 14日5 8418149.1%

12815 352 22 26 lud2 df- 22- a) P-value 7095 stud 2 valueco.os 0-025 P- Value