Question

Problem 2.29 A 50-MHz generator with Z, 50 2 is connected to a load 2L = (50_/25) Ω The time-average power transferred from the generator into the load is maximum when Zg = , where ZL is the complex this condition without changing Zg, the effective load impedance can be modified by adding an open-circuited line in series with Zu, as shown in Fig. line's Zo-: 100 Ω, determine the shortest length of line (in wavelengths) necessary for satisfying the maximum-power-transfer condition. conjugate of Zt. To achieve 2-40 (P2.29). If the 20 = 100 52 50Ω 50-25) Ω Zg

Please show all your work clearly and write out explanations. I know the solution involves a cotangent equation but I don't know where it comes from. Can you please show a derivation for that equation? thanks

Answer 1

ven rt 50几 maximum posep Conditron of m pecance c he

So Zir SD , ,50 み - ,3258 3 So 2 3258 メニ O-2/1