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Suppose that a researcher, using wage data on 230 randomly selected male workers and 258 fermale workers, estimates the OLS r

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4. The given model is:
Wage = 11.518+1.95 Male

a. In this model, the coefficient of the dummy variable iss 1.95. Average wage of females is 11.518. Average wage of males is 13.468. The estimated wage gap between males and females is 1.95.

b. The t statistic is:
west 81-87 1.95 - SET 0.3312-5.88

c. The p-value corresponding to this t statistic is computed using the t table for 486 degrees of freedom. Since number of degrees of freedom is greater than 30, this value can be estimated using the standard normal distribution. The largest value in the z table is 3.99. p-value corresponding to that value is 0.000015~0.0001.

d. The p-value denotes the maximum probability of type 1 error which is the level of significance. Since this p-value is less than 5%, 1%, and 0.01%, therefore, it is statistically significant under all these levels of confidence.

e. The 95% confidence interval is computed by finding the t-values corresponding to 0.05 level of significance for a one tailed test. Since the number of degrees of freedom is very large, standard normal distribution can be used to estimate this confidence interval. The confidence interval is:
1.950 +1.96 0.3312-1-1.3.2.59)

f. From the sample, average wage of women is the avergae wage when the dummy variable male is equal to 0. This value is 11.518.

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