Question

subject -nutrition

Part 2 Nutrient Bioenergietics in Exercise and Training PER SONAL HEALTH AND EXERCISE NUTRITION 6.2 Predicting Energy Expenditure During Treadmill Walking and Running 8. A linear relationship exists between oxygen uptake or energy Predicting Energy Cost of Treadmill expenditure and walking speeds between 3.0 and 5.0kmh Walking (1.9 and 3.1 mph) and running at speeds faster than 8.0 km h (5-10 mph). Adding the resting oxygen uptake to the oxygen requirements of both the horizontal and vertical components of A 55-kg person walks on a treadmill at 2.8 mph (23 the walk or run makes it possible to estimate total (gross) exer- 2682-75 m-min ! ) up a 4% grade. Calculate: (1) cise oxygen uptake (Vo,) and energy (kcal) expenditure. (mL kg 1 min-1), (2) METs, and (3) energy expendte (kcal-min-i ). [Note: express % grade as a decimal vak i.e., 4% grade = 0.04.] Basic Equation Vo2 (mL-kg-l, min-i ) = Resting component ( 1 metabolic equivalent [METI: 3.5mLO2-kgc ponent (speed, m-min-1 x oxygen cost of horizontal move- ment) + vertical component (percent grade × speed, m-min-1 x oxygen cost of vertical movement). Predicting Energy Cost of Treadmill Running 1.min-1) + horizontal com- Problem 2 A 55-kg person runs on a treadmill at 5.4 mph (56x 26.82 [To convert mph to m-min ,multiply by 26 82; to convert m-min- to mph, multiply by 0.03728.] 1. Walking: Oxygen cost equals 0.1 mL.kg 1 min-1 for the horizontal component of movement and 1.8 mL.kg1.min- for the vertical component. 2. Running: Oxygen cost equals 0.2 mL.kg 1 min-1 for the horizontal component of movement and 0.9 mL.kg1.min for the vertical component 145 m min i up a 6%grade. Calculate: (1)V in mL-kg-1, min-l, (2) METs, and (3) energy expend (kcal min 1). the Point Visit the Point.Iww.com/MKKSENe b answers to these questions

Answer 1

Problem 1

Given, person is walking on the treadmill, Body mass = 55 kg, Speed = 75 m.min^-1, Percent grade = 4% = 0.04, Oxygen cost of horizontal movement (When walking) = 0.1 mL.kg^-1.min^-1 (Given in basic equation), Oxygen cost of vertical movement (When walking) = 1.8 mL.kg^-1.min^-1 (Given in basic equation), Resting $\dot{V}$O₂ = 3.5 mL.kg^-1.min^-1

(1) Now, $\dot{V}$O₂ (mL.kg^-1.min^-1) = Resting component + Horizontal component + Vertical component (Given in basic equation)

= Resting $\dot{V}$O₂ (mL.kg^-1.min^-1) + [Speed (m.min^-1) x Oxygen cost of horizontal movement (mL.kg^-1.min^-1)] + [Percent grade x speed (m.min^-1) x oxygen cost of vertical movement (mL.kg^-1.min^-1)]

= 3.5 + (75 x 0.1) + (0.04 x 75 x 1.8) = 3.5 + 7.5 + 5.4 = 16.4 mL.kg^-1.min^-1

(2) Now, METs = Work metabolic rate/ Resting metabolic rate = 16.4/3.5 (Work metabolic rate is calculated in part (1) & Resting metabolic rate is given in basic equation) = 4.69 (Up to 2 decimal)

(3) Energy expenditure (kcal.min^-1) = $\dot{V}$O₂ (mL.kg^-1.min^-1) x Body mass (kg) x 5.05 kCal.L^-1

= 16.4 mL.kg^-1.min^-1 x 55 kg x 5.05 kCal.L^-1 = 902 mL.min^-1 x 5.05 kCal.L^-1 = 0.902 L.min^-1 x 5.05 kCal.L^-1 = 4.56 kCal.min^-1(Up to 2 decimal)

Problem 2

Given, person is running on the treadmill, Body mass = 55 kg, Speed = 145 m.min^-1, Percent grade = 6% = 0.06, Oxygen cost of horizontal movement (When running) = 0.2 mL.kg^-1.min^-1 (Given in basic equation), Oxygen cost of vertical movement (When running) = 0.9 mL.kg^-1.min^-1 (Given in basic equation), Resting $\dot{V}$O₂ = 3.5 mL.kg^-1.min^-1

(1) Now, $\dot{V}$O₂ (mL.kg^-1.min^-1) = Resting component + Horizontal component + Vertical component (Given in basic equation)

= Resting $\dot{V}$O₂ (mL.kg^-1.min^-1) + [Speed (m.min^-1) x Oxygen cost of horizontal movement (mL.kg^-1.min^-1)] + [Percent grade x speed (m.min^-1) x oxygen cost of vertical movement (mL.kg^-1.min^-1)]

= 3.5 + (145 x 0.2) + (0.06 x 145 x 0.9) = 3.5 + 29 + 7.83 = 40.33 mL.kg^-1.min^-1

(2) Now, METs = Work metabolic rate/ Resting metabolic rate = 40.33/3.5 (Work metabolic rate is calculated in part (1) & Resting metabolic rate is given in basic equation) = 11.52 (Up to 2 decimal)

(3) Energy expenditure (kcal.min^-1) = $\dot{V}$O₂ (mL.kg^-1.min^-1) x Body mass (kg) x 5.05 kCal.L^-1

= 40.33 mL.kg^-1.min^-1 x 55 kg x 5.05 kCal.L^-1 = 2218.15 mL.min^-1 x 5.05 kCal.L^-1 = 2.21815 L.min^-1 x 5.05 kCal.L^-1 = 11.20 kCal.min^-1(Up to 2 decimal)