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6.16 Shown in Fig. P6.16 is the ac equivalent of a bipo- lar differential amplifier driving a load consisting of R, and G. Le
(a) Use the half-circuit technique to find the low frequency value as well as the zero frequencjy and the two pole frequencie
6.16 Shown in Fig. P6.16 is the ac equivalent of a bipo- lar differential amplifier driving a load consisting of R, and G. Let the BIT's have g""-1/(50 Ω). As 250, o 120 kQ, r,-250 Ω'f_ 400 MHz, C0.45 pF and CI pE. Moreover, let R,- 2.0 kQ. Rc10 kL. Ri-50 k2, and C-4.5 pF. Rc Rc RL CL 02 01 CEE REE FIGURE P6.16
(a) Use the half-circuit technique to find the low frequency value as well as the zero frequencjy and the two pole frequencies of a if). What is the GBP of this amplifier? (b) Use the half-circuit technique to estimate the low-frequency value as well as the zero fre- quency of acmun if REE-3 ΜΩ and CEE- 0.35 pF.
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6-16 G.O 277 -12 150 7.16 Common -made ha afecut aiso Rc. 2REE 2T REE CEE

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