Solution:- (d) E(x) = 5.25
Heads(x) | P(x) |
0 | 0.25 |
1 | 0.5 |
2 | 0.25 |
Sum | 1 |
E(x) = P(Two heads)*10 + P(One Heads)*5+P(No Heads)*1
E(x) = 0.25*10 + 0.50*5 + 0.25*1
E(x) = 2.5 + 2.5 + 0.25
E(x) = 5.25
3) In a game of chance you're given two quarters to flip. Two heads are worth 10 points one head is worth 5 poi...
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