1)
The reaction is:
CH4(g) + 2 O2(g) —> CO2(g) + 2 H2O(g)
2)
Molar mass of CH4,
MM = 1*MM(C) + 4*MM(H)
= 1*12.01 + 4*1.008
= 16.042 g/mol
mass of CH4 = 4.2*10^2 g
mol of CH4 = (mass)/(molar mass)
= 4.2*10^2/16.04
= 26.18 mol
According to balanced equation
mol of CO2 formed = moles of CH4
= 26.18 mol
Given:
P = 1.0 atm
n = 26.18 mol
T = 17.0 oC
= (17.0+273) K
= 290 K
use:
P * V = n*R*T
1 atm * V = 26.18 mol* 0.08206 atm.L/mol.K * 290 K
V = 623 L
Answer: 623 L
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