Design the T-section beam then design the circular-spiral column on A accordingly. (A is on the hinge)
Given: f'c=28 MPa fy=420 MPa
Design the T-section beam then design the circular-spiral column on A accordingly. (A is on the hinge) Given: f'c=28...
Design circular-spiral column on A. (A is on the hinge)
Given: f'c=28 MPa fy=420 MPa
Wo 40 kN/m and WL 15 kN/m 2.5 m
Wo 40 kN/m and WL 15 kN/m 2.5 m
Design the T-section beam for the following:
Given: f'c=28 MPa fy=420 MPa
Wo 40 kN/m and WL 15 kN/m 2.5 m
Wo 40 kN/m and WL 15 kN/m 2.5 m
Assignment # 2 niath For the cantilever beam shown below, design for the dimensions and the deals flexural steel reinforcement if the Live load is qual to 8 kN/m and the Dead load is equal to beam own weight adding to 5 kN/m. And draw the stress-strain distribution. U T 3 m 300 mm Section A-A Given: f'c=28 MPa Cover= 40 mm 1,= 420 MPa d stir = 10 mm E,= 200000 MPa Yconcrete = 25 kN/m? B, = 0.85...
Assignment # 2 nath For the cantilever beam shown below, design for the dimensions and the deals flexural steel reinforcement if the Live load is qual to 8 kN/m and the Dead load is equal to beam own weight adding to 5 kN/m. And draw the stress-strain distribution. U I 3 m 300 mm Section A-A Given: f'c=28 MPa Cover= 40 mm 1, = 420 MPa d stir = 10 mm E,= 200000 MPa Yconcrete 25 kN/m B, = 0.85...
design an axially loaded short round spiral column to support an axial dead load DL=X an axial live load of LL=Y pg=0.02 as first trial fc=21 mpa fy=420mpa fyt=420 mpa X=1500 KN Y=1750 KN by using ACI 318-14 and ASCE equations
Ql: design short tied column to carry dead load 1600 kN and live load 1400 kN. 28 N/mm and Ty -420 N/mm Q2: design circular column spirally reinforced subjected to the following loads P 1000 kN Use fc-28 N/mnn, and fy =420 N/m rm2 Q 3: The 300 x 500 mm column shown in Fig. Q3 is reinforced with 8 No. 29 bars arranged around the column perimeter, providing an area Ast 5160 mm2. A factored load Pu of 1...
2. For the beam and loading shown, design the cross section of the beam, knowing that the grade of timber used has an allowable normal stress of 12 MPa 2.5 KN 2.5 KN 100 mm 6 kN/m 0.6 m 0.6 m 3. Knowing that the allowable normal stress for the steel used is 160 MPa, select the most economical S shape beam to support the loading shown. SO KN 100 kN/m B 0.8m- 1.6 m
2. Given a simply supported beam shown in figure below with the cross section at maximum moment. The beam supports a uniform service dead load of WDL =30 kN/m (excluding own weight of beam), Pll = 270 kN. Use fc' = 30 MPa; fy = 400 MPa. Calculate design strength OMn for the cross section shown in the figure. Check the strains in the steel esi. LL , 75-40-100 -775 90 90 WOL 710 650 5030 -15000 mm
simply supported reinforced concrete beam of rectangular section is hung on the left end by a 400mm square post working in tension, as shown in the figure below. The beam supports a uniform dead load (DL) gf 100 KN/m (excluding its own weight) and upiform live load LL) of 40KN/m. The beam is reinforced with 025 longitudinal rebars with 40mm cleat cover to the stirrups. Material properties: fy 420 MPa, fe 25 MPa. Beam dimension b 400mm and h 600mm....
Example 2: Design the staircase shown below as transversely spanning, givendata: riser R = 175 mm, tread T = 300 mm, f'c = 25 MPa, fy = 300 MPa, yc= 24 kN/m3, finishing load = 1.0 kN/m2, live load = 3.5 kN/m2.