Question

FIRST RUN: (a) Mass of the Calorimeter (two empty cups) in g: 4.0g

(b) Mass of the cold water and the calorimeter in g: 52.5g

(c) Calculated mass of the coldwater in g [(b)-(a)]: 48.5

(d) Temp. of the Cold Water in C: 14c

(e) Temp. of the Hot Water before mixing with the cold in C: 38c

(f) Mass of the Cold & hot water mixed AND the calorimeter in g: 100.6g

(g) Calculated Mass of the Hot water in g [(f)-(b)]: 48.1g

(h) Temperature of the mixed hot & cold water in C: 26c

(i) Calculated Heat Lost by the Hot Water in

J (SHOW WORK and answer!!), q=mcDt, (Mass of Hot Water in g)(4.18J/gC)(Mixed Temp - Hot Water Temp): Yes, it should be a negative value! q(hot)=m(hot)c(t is mixed-t is hot) =48.1g x 4.18 J/g. degrees C(26 C -38C) =201.058(-12) J = -2412.696J

(j) Calculated Heat Gained by the Cold Water in J (SHOW WORK and answer!!), q=mcDt, (Mass of Cold water in g)(4.18J/gC)(Mixed Temp - Cold Water Temp): Yes, it should be a positive value! q(cold)=m(cold)c(t is mixed-t is cold) =48.5g x 4.18 J/g. degrees C(26 C -14C) =202.73(12) J =2432.76J

how do I calculate theoretical final temperature?

Answer 1

(aMaRs a Calorimeter(two enpta ° b) Maes af cold woderf4ReCalorimsjtr:s2 CuPs 5-9)&48s३ -2-3 Magg Cf Cold water (52.5- Tem Cf Cold ater.T=4c fe Temp of Rat uwater before () - 3Rc miring witecold Mass ftRe colddot water 10 Mam Rat Warer (m GoS2 Tempof mmirod:Aat cohd Water()= 200 DHeat ost by Rot wJatsr aspecific Roa Cofwater 4.2 Heat *(26-3)3 ニー2-46KI ainsd b Coldwoter x.18(20-1) ン2-432CK) Salorimu )= m(T- T-14) s x38-48IT 48ST_44x48S ACCording to HH2 0 m2(T-) TRarilticly81( 38ーDン485 T=ス552 amScanner