Use the above sign convention Question 1 Calculate the internal member forces in section A, B and C shown in the follow...
2) Calculate the internal forces in each member of the truss shown below, and indicate if they are in tension (T) or compression (C). P1 4 kN and P2 4 kN 30° 3 m Im P2 2) Calculate the internal forces in each member of the truss shown below, and indicate if they are in tension (T) or compression (C). P1 4 kN and P2 4 kN 30° 3 m Im P2
300 N-m 500 N-m 3. Consider the torque-loaded member shown. Determine the internal torque in each section of the bar (that is, determine TAc. Tco, and Tos). a. 300 400 mm 500 mm Applying the standard sign convention for torsion, sketch a graph of the internal torque T as a function of x, where b. - distance along bar, beginning at point A.
A). For the truss shown, use the cut section a- a to find the internal forces in members AG, BG and BC. B). Find the internal forces in members CF and DF using the cut b-b. |--1.5 m-e-1.5 m --1.5 m-, TE 900 N 3 m 800 N 3 m 500 N
Calculate the internal forces in each member of the truss shown below, and indicate if they are in tension (T) or compression (C). P1 = 600 kN and P2 = 400 45° 45° 4 m 4 m 4 m 45° 45° 4 m 4 m 4 m
Determine the forces in each member of the truss shown in figure 11. Above. 120 KN 120 KN 4 m 120 KN H E F 60 KN 60 KN 4 m 40 KN 40 KN A B D 8 m +2 m|-3 m-3m|3m|3m|2m1 8 m Figure 11: A truss. GROUP 2B QUESTION 12: You have just graduated from CBU as a civil engineer. A water utility company employs you. During maintenance, in turning the water pump steadily, you exert a...
Question Three: For the truss shown below, find the the internal force in member No. 6 using section method. "M 5 m 5 m 40 KN 5 m 5 m Find the reactions at the supports. Find the internal forces in members 2 and 6. Show calculations. knowing that, M =92.49kN L =96.23kN 0= 40°
Determ ine the internal forces at point J for the structure shown, where member BD can only carry axial forces. Take the dimension a 176 mm and the external load P 500 M a mm 225 mm B 120 mm 225 mm A P NV 135 mm axial force: Number Units (tolerance 1 N, magnitude only) FJ shear force: SF= Number Units (tolerance 1 N, magnitude only) bending moment Number Units (tolerance 100 N mm, magnitude only) BMJ Determ ine...
QUESTION 1 [25 marks A frame loaded with a uniformly distributed load at Member AB and point load at Member BC and joint B. It has pinned supports A and C, while joint B is fixed connected, as can be seen in Figure 1. Take E-200 GPa. a) Using the slope-deflection method, calculate the moments and illustrate the bending moment diagram. [15 marks) b) Then calculate the shear forces and sketch the shear force diagram. [10 marks) 22 KN 10...
1) Using the section location (section S-S), Find the internal axial forces related. 2) Using the joint method, find the internal axial forces in all members of the truss shown below.P1 = 70K P2 = 130KN P3 = 90KN P4 = 80KN X1 = 3m X4 = 4.5mI need this by tomorrow, please
Determine all of the member forces in the truss below( take zero force members into consideration): Determine all of the member forces in the truss below: Question 1 11 points 5 kN 5 kN 8 m 5 kN A 4 m 4 m 4 m Use the strict tension positive sign convention for internal forces, accuracy 0.5kN Units Number Units FBC Number FAB = Number Units Units Number FCD FAG= Number Units Number Units FAF = FBF FCE Number Number...