The balanced equation for the detonation of nitroglycerin is shown below. If 10.0 moles of C3H5O9N3 react, how man...

Question

Question

Answer 1

Answer #1

Detonation of nitroglycerin reaction:

4 C3H5O9N3 (l) ---- > 12CO2(g) + 6N2(g )+ O2 (g) + 10 H2O (g)

Given that 10.0 moles C3H5O9N3

10.0 moles C3H5O9N3*10 mole H2O/4.0 moles C3H5O9N3 = 25 Moles H2O

Part 2

Number of moles = amount in g / molar mass

= 7.0g /207.2 g/ mole

= 0.0338 moles Pb

,moles of Ag can be calculated as follows:

0.0338 moles Pb*2 mole Ag / 1 mole Pb

= 0.0676 moles Ag

Amount in g = number of moles * molar mass

= 0.0676 moles Ag*107.8682 g/ mole

= 7.29189032 g Aag

= 7.3 g

Answer 2

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