When voltmeter is connected in series with resistance R1, it shows voltage U1 = 198 V, but turned on in series with R2 = R * R1, voltmeter shows U2 = 180 V. Find R1 and voltage in the network if voltmeter inner resistance r = 900 Ω.
When voltmeter is connected in series with resistance R1, it shows voltage U1 = 198 V, but turned on in series with R2 =...
in the circuit below we have that U1 = 10 [V], R1 = 120 [Ω], R2 = 230 [Ω], U2 = 16 [V], R3 = 450 [Ω] och J = 0.3 [A]. calculate the electric potential (voltage) in A and B. A B - RA ا U + | R2 میا
Two resistors, R1 and R2, are connected in series. a) calculate the single resistance equivalent (in Ω) to the series combination. b) Repeat the calculation for a parallel combination of R1 and R2. (Enter your answer in Ω.)
Two identical resistors, R1 and R2, are connected in parallel, and this parallel combination is then connected in series with a 100 Ω resistor, R3 as shown below If the total resistance of the circuit is 300 Ω what must be the resistance of R1 and R2? If the circuit is connected to a 30V battery, what would the current through R1? What voltage is a dropped across R3? 100 S
8-1 12. A voltmeter with an internal resistance of 3.08 10.2 measures the voltage R, in the following figure across Ri in the following figure: R1 10.0 kΩ (3 marks) R2 20.0 kΩ 275 V a. What is the voltage across Ri in the absence of the meter? b. Draw the circuit diagram with the meter in place and calculate the effective resistance of the circuit. c. What is the voltage across R1 with the meter connected across it?
Two resistances, R1 and R2, are connected in series across a 3-V battery. The current increases by 0.150 A when R2 is removed, leaving R1 connected across the battery. However, the current increases by just 0.075 A when R1 is removed, leaving R2 connected across the battery. (a) Find R1. ____? (b) Find R2. ____ ?
Internal resistance problem. Suppose that in Figure 3.3, Vo=13V, R1=150kΩ, R2=375kΩ, and Ri=2MΩ. Initially, the voltmeter is disconnected. If the internal resistance of the meter were 12 M Ω, what is the voltage across R2? Volts:
Two resistances, R1 and R2, are connected in series across a 12-V battery. The current increases by 0.25 A when R2 is removed, leaving R1 connected across the battery. However, the current increases by just 0.10 A when R1 is removed, leaving R2 connected across the battery. Find (a) R1 and (b) R2.
A battery provides a voltage of 8.00 V and has unknown internal resistance Rint. When the battery is connected across a resistor of resistance R1= 7.00 Ω , the current in the circuit is I1 = 1.00 A. If the external resistance is then changed to R2 = 5.00 Ω , what is the value of the current I2 in the circuit?
Internal resistance problem. Suppose that in Figure 3.3, Vo=10VVo=10V, R1=175kΩR1=175kΩ, R2=400kΩR2=400kΩ, and Ri=1MΩRi=1MΩ. Initially, the voltmeter is disconnected. EXAMPLES: What is the voltage across R2R2? [Answer: 6.95652173913043 V.] What is the voltage across R2R2 with the meter connected? [Answer: 6.2015503875969 V.] QUESTION: If the internal resistance of the meter were 14 M ΩΩ, what is the voltage across R2R2? Thanks ahead Voltmeter Figure 3.3: Circuit used to observe the effect of test equipment on a measurement.
Resistors R1 = 1.2 kΩ and R2 = 6.8 kΩ are connected in series with a 1.5 V cell in a single circuit loop. Find (a) the current through R1, (b) the voltage across R1, (c) the wattage of the resistor that dissipates the most energy. Answers: (a. 0.19 mA, b. 0.23 V, c. 0.24 mW (R2))