a)
X = have the disease
Y = test positive
P(X) = 0.03
P(Y|X) = 0.98
P(Y' | X') = 0.95
P(X|Y) = P(X and Y)/P(Y)
= P(Y|X)P(X) / ( P(Y|X) P(X) + P(Y | X')P(X'))
= 0.98 * 0.03 / (0.98*0.03 + 0.05 * (1-0.03))
= 0.377406
b)
false
this is because number of person who don't have disease is much
larger 97%
as compared to 3 % who have disease
c)
we have 37.74% probability that if we test positive then we actually have disease
this is not good test
ltis known that 3% ofthe Uk's population carry a certain disease. Atest forthe disease is available Leave 5 whi...
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