Question

4) 440 pnts) A solution is prepared by mixing some volume of methanol (MM = 32.04 g/mol, d=0.792 g/mL, p = 94.0 torr) and acetone (MM=58.07 g/mol, d=0.784 g/mL, Pº = 240. torr) at room temperature. Assuming that the volumes additive on mixing. a) What is the mole fraction of acetone and methanol in solution if the number of acetone and methanol gas molecules above the solution are equal to one another? Assume ideal solution behavior.

Answer 1

Solution: say, no of gas molecules for each gas - inn. .. no. of moles of acetone - N - NA - Avogadro no. No. of moles of methanol = a un NA total no. of moles - 2 a - mole fraction of acetone - 2n mole fraction of 2 A = 0,5 N methanal = 0,5 N NA 0, 2 N