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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of

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2 mol Koh IL of 0.9M HEN = 1x0.9 = o amol HEN hence kon is m more amount than her => bases 0,1 mol of KOH 12 of 0.3M both HENplease give thumbs up to my answer as I am in very need of that do comment for any of your doubt

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