Question

2) 4NH3(g) + 302(g) + 6H2O(l) + 2N2(g) (a) 2 moles of NH, and 3 moles of Oz will produce ? moles Nz? (b) 5.0 g of NH, and 5.0 g of Oz will produce ? g of H2O? How many H2O molecules? 3) A mixture of 80.0 g of chromium (VI) oxide, Cr2Os, and 8.00 g of solid carbon, C, is used to produce elemental chromium, Cr, by the reaction below Cr2O3(aq) + 3C (s) → 2Cr (s) + 3C0 (9) a) Which reactant is the limiting reagent? b) What is the theoretical yield of Cr that can be obtained from the reaction mixture?

Answer 1

Answer

4 With g t 30 (9, 6H 4 + 2 g Balanced equation chans that 4 moles the reacts Completely with 3 mol og Tuus, 2 mol Nth will react completely with 1.5 mol Og. But Og available = 3 mol So Nho is the limiting reagent and decides the amount of N formed - 4 moe Nh reacts completely to form Na = 2 2 mol NH will react completely to form N = 2 mol x 2m umor 1 mol Molar mass of NH = 17g mot molar mass of 0 - 32 g mot molar mass of Ho = 189 mat mass of 4mor NH & 4 mol x 17gmat mass of 3 0 30 - 3 mol x 32gmat MU - 9og egnet & mass of Ho - 6mol & 18 gmott - 128 g 1 68 g Why reacts completely with @ - 90g So I g WH with react completely with of 96g x5g - 7.05 g Thus why is the amount the of linting product reagent ferred and doules

68 g Nt rests completely to form the = 128 Sg WH will react completely to form the 108