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19. Ammonia and oxygen react to form nitrogen and water. 4NH3(g) + 302(g) 2N2 (g) + 6H,0 (g) a. How many grams of O, are need
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Vede Ro. 19. 4 NH3(g) + 30₂(g) → 2N2(g) + 6H2018) | @ Mass of Os needed - molar mass O2 X3x mass of NH! Molar mass NH3 X4 g 3Hope you will like my answer.

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