*NEED HELP PLEASE! ALSO Please show you got the Standard deviation to get the margin of error!**
Since there are lot of data points
I am going to tell you the formulas
X =number of success
n = total sample size
For example if we want to get confidence interval for those who answered poor to room quality
X = number of person who answered poor to room quality
now
p^ = X/n
here n = 200
say
X = 120 {note that I am just taking a guess, count yourself using Excel formulas}
then
p^ = X/n = 0.6
now
margin of error = z *sqrt(pq/n)
here z depends on confidence level
for 92% confidence level
z = normsinv(0.92 + (1- 0.92)/2) = 1.7507
hence
margin of error
= 1.7507 * sqrt(0.6 * (1-0.6)/200)
= 0.0606
confidence interval is
(p^ - margin of error , p^ + margin of error)
=(0.6- 0.0606 , 0.6 + 0.0606 )
= ( 0.5394 , 0.6606 )
Please rate
Please note again that I took X as 120 randomly if you calculate yourself and repeat the process
Thanks
*NEED HELP PLEASE! ALSO Please show you got the Standard deviation to get the margin of error!** 1. To summarize the...
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