Question

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2 mol LioH gLicos738g Lcsmal Li 35,0 CO3 0.947 mol iOH Methard can be formed by follawing uabalanced equaten How can be farmed fram lol moleculas of CO Ho + COCH30H mele Go Co.023x (023 malecutes below many grams ct methanol lal mdegudas Co 3ag ImaleeH3OH 536 609&1033 le 3232 6,0231025 5,37 x JO men texe lew" They Say answer wasS What did i do wrang

Answer 1

2H₂ + co 2 mole / Imole I=6.023X10²3 CH₂ OH I imole = 32g : 6:02 3 X1023 molecules of cofradbees 32 g CH3OH i 101 6023 X 1023 - 32 X101 g 6.023x1023!? = 3232 x 10-23 6.023 0 = 536.6 X10-23 9 = 5.37 X 10 g methanol