Question 2* Consider th following twelve diagrams A,... , L C: G: I: K: (a) Each diagram represents a simple graph of o...
Question 2* Consider th following twelve diagrams A,... , L C: G: I: K: (a) Each diagram represents a simple graph of order 6 with exactly one circuit, but not all graphs are different. When X, Y represent the same graph we write XY. For example, A B. Partition the set {A, B,, Ly using the equivalence relation. (b) Any hydrocarbon molecule consists of joined-up carbon and hydrogen atoms, and can be represented by a connected graph in which each C has degree 4 and each H has degree 1. The subgraph of C atoms and edges between them is sometimes called the 'skeleton' of the molecule. When this skeleton is a tree, the molecule is 'saturated' (as we have seen). When it is simple but not a tree it is 'cyclic saturated'. All the diagrams in (a) correspond to skeletons of monocyclic saturated isomers of the hydrocarbon C6H12. For diagrams D, and H draw a full molecule structure diagram by 'hanging off' H's from C's at all appropriate places. Any valid layout is acceptable. (c) The standard naming convention of hydrocarbon isomers is entirely based on the graph theoretic properties of the skeleton. For example the isomer corresponding to diagram A is called propylcyclopropane, which means a 3 ('prop') carbon-chain ('yl') attached to a circuit (cyclo') of 3 ('prop' again) minimally-linked carbons ('ane') With the help of http://www.chemspider.com/Search.aspx?q c6h12, give a full chemical name for the two isomers whose structure diagram you drew for (b) (Prefixes 'meth', 'eth', 'prop', 'but' mean 1,2,3,4. When used, digits show positions Special skeleton shapes convey geometric information not relevant to this question.)
Question 2* Consider th following twelve diagrams A,... , L C: G: I: K: (a) Each diagram represents a simple graph of order 6 with exactly one circuit, but not all graphs are different. When X, Y represent the same graph we write XY. For example, A B. Partition the set {A, B,, Ly using the equivalence relation. (b) Any hydrocarbon molecule consists of joined-up carbon and hydrogen atoms, and can be represented by a connected graph in which each C has degree 4 and each H has degree 1. The subgraph of C atoms and edges between them is sometimes called the 'skeleton' of the molecule. When this skeleton is a tree, the molecule is 'saturated' (as we have seen). When it is simple but not a tree it is 'cyclic saturated'. All the diagrams in (a) correspond to skeletons of monocyclic saturated isomers of the hydrocarbon C6H12. For diagrams D, and H draw a full molecule structure diagram by 'hanging off' H's from C's at all appropriate places. Any valid layout is acceptable. (c) The standard naming convention of hydrocarbon isomers is entirely based on the graph theoretic properties of the skeleton. For example the isomer corresponding to diagram A is called propylcyclopropane, which means a 3 ('prop') carbon-chain ('yl') attached to a circuit (cyclo') of 3 ('prop' again) minimally-linked carbons ('ane') With the help of http://www.chemspider.com/Search.aspx?q c6h12, give a full chemical name for the two isomers whose structure diagram you drew for (b) (Prefixes 'meth', 'eth', 'prop', 'but' mean 1,2,3,4. When used, digits show positions Special skeleton shapes convey geometric information not relevant to this question.)