only question 61 Find the area of the base of the right regular pyramid. Then find its total surface area. Give th...

Question

Question

only question 61

Answer 1

Answer #1

a=10

Base area of prism=area of hexagon= $\frac{3\sqrt{3}a^2}{2}$ = $3V310$ = 259.8076 sq. meters

Total surface area= base area of prism + 6*six triangular face

= 259.8+6*1/2*10*21 = 889.8076 sq meters= 889.8 sq.meters in nearest tenth

Answer 2

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