a) (CH3)3OK is stronger base because of +I effect of three CH3 groups, electron density on oxygen increases thus, basicity increases.
b) HCCNa is stronger
base because negative charge on carbon is less stabilized as
compared to negative charge on oxygen in CH3CH2ONa.
c) NaNH2 is strong base than HCCNa because NH3
is weakly acidic and Alkyne is strong acid.
d) NaCN is strong base because HCN us weakly acidic as compared to HI.
please explain your answers 3. Circle the stronger base in each pair. (0.2 pts ea = 2,0 pts) a. (CH3) COK vs. CH3OK...
Circle the stronger base in each pair
3. Circle the stronger base in each pair. (0.2 pts ea = 2.0 pts) a. (CH3) 3COK vs. CH3OK b. HCECNa vs. CH3CH2ONa C. NaNH2 vs. HCECNa d. NacN vs. NaI e. NaHCO3 vs. NaOH f. NaOH vs. CoH5CO2Na g. C6H5COzNa vs. CoH5ONa h. CH3CO2Na vs. CH3ONa i. CH3ONa vs. NaH j. NH3 vs. CH3CO2Na
please explain your answers
3. Circle the stronger base in each pair. (0.2 pts ea = 2.0 pts) a. (CH3) 3COK vs. CH3OK b. HCECNa vs. CH3CH2ONa c. NaNH2 vs. HCECNA d. NaCN vs. NaI e. NAHCO3 vs. NaOH f. NaOH vs. C6H5CO2Na g. C6H5CO2Na vs. C6H5ONa h. CH3CO2Na vs. CH3ONa i. CH3ONa vs. NaH j. NH3 vs. CH3CO2Na
Circle the stronger base in each pair- answers only. No
explanations, no incomplete answers.
3. Circle the stronger base in each pair. (0.2 pts ea 2.0 pts) a. (CH3) 3COK vs. CH3OK b. HCECNa vs. CH3CH2ONa c. NaNH2 vs. HCECNa d. NaCN vs. NaI e. NaHCO3 vs. NaOH CoH5CO2Na f. NaOH VS. g. C6H5CO2Na vs. CoH5ONa h. CH3CO2NA vs. CH3ONa CH3ONA vs. NaH i. NH3 vs. CH3CO2Na j.
Circle the stronger BASE in each pair. No explanation, no
incomplete answers. I have 4 of these correct so I will know if
you’re getting them wrong.
3. Circle the stronger base in each pair. (0.2 pts ea = 2.0 pts) a. (CH3) 3COK vs. CH3OK b. HCECNa vs. CH3CH2ONa C. NaNH2 vs. HCECNa d. NacN vs. NaI e. NaHCO3 vs. NaOH f. NaOH vs. CoH5CO2Na g. C6H5COzNa vs. CoH5ONa h. CH3CO2Na vs. CH3ONa i. CH3ONa vs. NaH j. NH3...
please explain your answer
4. This question continues on the next page. For each of the following acid-base reactions: (0.3 pts ea = 3.0 pts) a. Predict the products that could form. b. Next to the products you draw, write either "Products not favored" or "Products favored." a. CH3OH + NaH → b. NaOH + CH3OH → C. KOH + (CH3)3COH → d. CH3OH + HI → dan gelen o e. HCECNa + CH3CH2OH → TH f. HCECH + CH3Li...
please explain your answers
5. Circle all of the bases below that can be used successfully to deprotonate CH3OH. (0.3 pts) a. CH3CO2Na b. KOH C. NH3 d. NaHCO3 e. NaNH2 f. NaH
please explain your answers
4. This question continues on the next page. For each of the following acid-base reactions: (0.3 pts ea = 3.0 pts) a. Predict the products that could form. b. Next to the products you draw, write either Products not favored" or "Products favored." a. CH3OH + NaH CHO Na + H₂ products favored b. NaOH + CH3OH → CH₂O N2 + H₂O products favored C. KOH + (CH3)3COH (CH3), COK + H20 products favored d. CH₃OH...