Sol :-
(a). (CH3)3COK is stronger base than CH3COK, because in (CH3)3COK has three electron donating groups that is +I -CH3 groups which increase the electron density on oxygen atom and make it a strong base. While CH3COK only contains one -CH3 group.
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(b). HC≡CNa is stronger base than CH3CH2ONa, because in HC≡CH is weaker acid than ethanol C2H5OH, therefore its conjugate base HC≡C- must be stronger base than conjugate base C2H5O- of C2H5OH.
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(c). NaNH2 is stronger base than HC≡CNa, because in NH3 is weaker acid than HC≡CH, therefore its conjugate base NH2- must be stronger base than conjugate base HC≡C- of HC≡CH.
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(d). NaCN is stronger base than NaI, because in HCN is weaker acid than HI, therefore its conjugate base CN- must be stronger base than conjugate base I- of HI.
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(e). NaOH is stronger base than NaHCO3, because in NaHCO3 is the salt of strong base NaOH and weak acid H2CO3. On the other hand NaOH is the stronger base.
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(f). NaOH is stronger base than C6H5COONa, because in C6H5COONa is the salt of strong base NaOH and weak acid C6H5COOH. On the other hand NaOH is the stronger base.
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(g). C6H5ONa is stronger base than C6H5COONa, because in C6H5OH is weaker acid than C6H5COOH, therefore its conjugate base C6H5O- must be stronger base than conjugate base C6H5COO- of C6H5COOH.
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(h). CH3ONa is stronger base than CH3COONa, because in CH3OH is weaker acid than CH3COOH, therefore its conjugate base CH3O- must be stronger base than conjugate base CH3COO- of CH3COOH.
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(i). NaH is stronger base than CH3ONa, because NaH gives strong base NaOH when dissolve in water.
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(j). NH3 is stronger base than CH3COONa. Because nitrogen in NH3 good electron donar than oxygen in CH3COONa.
Circle the stronger BASE in each pair. No explanation, no incomplete answers. I have 4 of these correct so I will know...
Circle the stronger base in each pair- answers only. No explanations, no incomplete answers. 3. Circle the stronger base in each pair. (0.2 pts ea 2.0 pts) a. (CH3) 3COK vs. CH3OK b. HCECNa vs. CH3CH2ONa c. NaNH2 vs. HCECNa d. NaCN vs. NaI e. NaHCO3 vs. NaOH CoH5CO2Na f. NaOH VS. g. C6H5CO2Na vs. CoH5ONa h. CH3CO2NA vs. CH3ONa CH3ONA vs. NaH i. NH3 vs. CH3CO2Na j.
Circle the stronger base in each pair 3. Circle the stronger base in each pair. (0.2 pts ea = 2.0 pts) a. (CH3) 3COK vs. CH3OK b. HCECNa vs. CH3CH2ONa C. NaNH2 vs. HCECNa d. NacN vs. NaI e. NaHCO3 vs. NaOH f. NaOH vs. CoH5CO2Na g. C6H5COzNa vs. CoH5ONa h. CH3CO2Na vs. CH3ONa i. CH3ONa vs. NaH j. NH3 vs. CH3CO2Na
please explain your answers 3. Circle the stronger base in each pair. (0.2 pts ea = 2.0 pts) a. (CH3) 3COK vs. CH3OK b. HCECNa vs. CH3CH2ONa c. NaNH2 vs. HCECNA d. NaCN vs. NaI e. NAHCO3 vs. NaOH f. NaOH vs. C6H5CO2Na g. C6H5CO2Na vs. C6H5ONa h. CH3CO2Na vs. CH3ONa i. CH3ONa vs. NaH j. NH3 vs. CH3CO2Na
please explain your answers 3. Circle the stronger base in each pair. (0.2 pts ea = 2,0 pts) a. (CH3) COK vs. CH3OK b. HCECNa vs. CH3CH2ONa c. NaNH2 vs. HCECNa d. NacN vs. NaI e. NaHCO3 vs. NaOH f. NaOH vs. CoH5CO2Na g. C.H.COŻNa vs. CoHsONa h. CH3CO2Na vs. CHEONa u dotos i. CH3ONa vs. Nah j. NH3 vs. CH3CO2Na
please explain your answer 4. This question continues on the next page. For each of the following acid-base reactions: (0.3 pts ea = 3.0 pts) a. Predict the products that could form. b. Next to the products you draw, write either "Products not favored" or "Products favored." a. CH3OH + NaH → b. NaOH + CH3OH → C. KOH + (CH3)3COH → d. CH3OH + HI → dan gelen o e. HCECNa + CH3CH2OH → TH f. HCECH + CH3Li...