Question

The heat capacity of an object indicates how much energy that object can absorb for a given increase in that object's temperature. In a system in which two objects of different temperatures come into contact with one another, the warmer object will cool and the cooler object will warm up until the system is at a single equilibrium temperature.

Note the difference between the terms molar heat capacity, which has units of J/(mol⋅∘C), and specific heat, which has units of J/(g⋅∘C).

Part A:

A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If the final temperature of the system is 21.20  ∘C , what is the mass of the steel bar?

Use the following values:

specific heat of water = 4.18 J/(g⋅∘C)

specific heat of steel = 0.452 J/(g⋅∘C)

Part B:

The specific heat of water is 4.18 J/(g⋅∘C). Calculate the molar heat capacity of water.

Express your answer to three significant figures and include the appropriate units.

Answer 1

1) Heat gained by metal bar - Heat lost by water С – МоАЛ x үед сва» ХДТ suppose nad temperature re man rod y Crod y otrod = maxswary & Curates y otwater - MX 0.452 X (21-20-2.00) = losy 4. 184 x ( 22.00 - 21.20) M = 40.5 grama [maps of water-volume x density - 105 x istme =1058] 2) Molor Heat capacity = # specific heat - 41 164 = 0.2324 57 mole C) moler mom 0.232

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