Ka = 1.37*10^-4
pKa = - log (Ka)
= - log(1.37*10^-4)
= 3.863
use:
pH = pKa + log {[conjugate base]/[acid]}
4.28 = 3.863+log {[lactate]/[lactic acid]}
log {[lactate]/[lactic acid]} = 0.4167
[lactate]/[lactic acid] = 2.61
[lactic acid]/[lactate] = 1/2.61 = 0.383
Answer: 0.383
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