calculate delta H for the reaction 4Cu(s)+O2(g)=2Cu2O(s) given the following hypothetical data 2Cu(s)+O2(g)=2CuO(s) delt...

Question

Question

calculate delta H for the reaction

4Cu(s)+O2(g)=2Cu2O(s)

given the following hypothetical data

2Cu(s)+O2(g)=2CuO(s) delta H=-312 kJ

2Cu2OtO2(g)=4CuO(s) delta H=-340kJ

deltaH=

Answer 1

Answer #1

Lets number the reaction as 0, 1, 2 from top to bottom

required reaction should be written in terms of other reaction

This is Hess Law

required reaction can be written as:

reaction 0 = +2 * (reaction 1) -1 * (reaction 2)

So, ΔHo rxn for required reaction will be:

ΔHo rxn = +2 * ΔHo rxn(reaction 1) -1 * ΔHo rxn(reaction 2)

= +2 * (-312) -1 * (-340)

= -284 KJ

Answer: -284 KJ

Answer 2

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