Question

Periodic Table OWLV2 Online teaching and learning resource from Cangage An iron nail rusts when exposed to oxygen. For the following reaction, 0.387 moles of iron are mixed with 0.258 moles of oxygen gas. iron(s) + oxygen(g) → iron(III) oxide(s) What is the formula for the limiting reagent? 5 M ots What is the maximum amount of iron(III)oxide that can be produced? pots moles I pts 2re 1 pts 2re Submit Answer Retry Entire Group 9 more group attempts remaining 11 pts 1 pts2rea O 1 pts 2reg Ipts 2eg 1 pts 2rea (Previous Next Show Mint Email Instructor Save and

Answer 1

The reaction that occurs in:

4Fe + 3 O2 = 2 Fe2O3

The limit reagent is O2.

Maximum moles of Fe2O3 are calculated:

n Fe2O3 = 0.258 mol O2 * (2 mol Fe2O3 / 3 mol O2) = 0.172 mol

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