Question

An iron nail rusts when exposed to oxygen. According to the following reaction, how many grams of oxygen gas are necessary to form 0.364 moles iron(III) oxide? iron (s) + oxygen (g) fron(III) oxide (8) grams oxygen gas

Answer 1

the balanced equation is as follows

4 Fe + 3 O2 -------------------> 2 Fe2O3

from the equation the 3 moles of O2 produces the 2 moles of Fe2O3

3 mol O2 -----------------------> 2 mol Fe2O3

? --------------------------------> 0.364 moles

=> 0.364 * 3 / 2

=> 0.546 moles

mass = moles * molar mass

for O2 = 0.546moles * 32 g/mol

mass = 17.472 grams

answer => 17.472 grams of oxygen gas