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find a. the 95% confidence interval has s lower limit of $____ and an upper limit of $_____ find b. what is the margi...
The average selling price of a smartphone purchased by a random sample of 43 customers was...
The average selling price of a smartphone purchased by a random sample of 43 customers was $315. Assume the population standard deviation was $34. a. Construct a 95% confidence interval to estimate the average selling price in the population with this sample. b. What is the margin of error for this interval? a. The 95% confidence interval has a lower limit of and an upper limit of. (Round to the nearest cent as needed.) b. The margin of error is....
The confidence interval lower limit and upper limit for a population mean are (43.5, 47.9). What...
The confidence interval lower limit and upper limit for a population mean are (43.5, 47.9). What is the sample mean and the margin of error for the sample.A sample of size 36 with ¯xx¯ = 45.7 and ss = 12.4 is used to estimate a population mean μμ. Find the 70% confidence interval for μμ. Sample mean = Margin of error =
Construct a 95% confidence interval to estimate the population mean with x overbar =118 and sigma...
Construct a 95% confidence interval to estimate the population mean with x overbar =118 and sigma =32 for the following sample sizes. a) n = 32 b) n = 43 c) n = 65 a) With 95% confidence, when n=32, the population mean is between the lower limit of ___ and the upper limit of ___. (Round to two decimal places as needed.) b) With 95% confidence, when n=43, the population mean is between the lower limit of...
Construct a 99% confidence interval to estimate the population mean using the data below. X =...
Construct a 99% confidence interval to estimate the population mean using the data below. X = 46 o = 12 n42 With 99% confidence, when n = 42 the population mean is between a lower limit of (Round to two decimal places as needed.) and an upper limit of Construct a 95% confidence interval to estimate the population mean with X = 102 and o = 25 for the following sample sizes. a) n = 32 b) n = 45...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals$5, standard deviation equals$19 The required sample size is __.
Construct a 95% confidence interval to estimate the population mean with x=101 and σ=27 for the...
Construct a 95% confidence interval to estimate the population mean with x=101 and σ=27 for the following sample sizes. a) n equals= 3030 b) n equals= 4343 c) n equals= 6464 a) With 95% confidence, when n=30, the population mean is between the lower limit of and the upper limit of. (Round to two decimal places as needed.) b) With95% confidence, when n=43, the population mean is between the lower limit of and the upper limit of. (Round to two...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error =$5,standard deviation=$25 The required sample size is ????? (Round up to the nearest whole number as needed.)
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals=$66, standard deviation equals=$2222 The required sample size is _____. (Round up to the nearest whole number as needed.)
Please Help I need the answers to below. Question 2: Construct a 95% confidence interval for...
Please Help I need the answers to below. Question 2: Construct a 95% confidence interval for the population mean. Assume that your data is normally distributed and σ is unknown. Include a statement that correctly interprets the confidence interval in context of the scenario. Calculations/Values Formulas/Answers Mean 72,224.34 Standard Deviation 22,644.46 n 364 Critical Value Margin of Error Lower Limit Upper Limit Question 3 construct a 99% confidence interval for the population mean. Assume that your data is normally distributed...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
Construct a 99% confidence interval to estimate the population mean using the data below. X = 46 o = 12 n42 With 99% confidence, when n = 42 the population mean is between a lower limit of (Round to two decimal places as needed.) and an upper limit of Construct a 95% confidence interval to estimate the population mean with X = 102 and o = 25 for the following sample sizes. a) n = 32 b) n = 45...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
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