Question

RT FOR EXPERIMENT 19 REPORT FOR INSTRUCTOR Charles' Law Data Table Trial 1 Trial 2 Temperature of boiling water, T.. Temperature of cold water, 9.8.", 370K 80.2C, 30AK 2020_ c, 295 K _"c, 29.SK Volume of water collected in flask (decrease in the volume of air due to cooling) 126.5 mL 24.9 mL Volume of air at higher tempera- ture, V (volume of flask measured only after Trial 2) Volume of wet air at lower tem- perature (volume of flask less volume of water collected), V. 144.9 mL 144.9 -26.5= 118.4mL luboomL 146.6-24.9 mL) | 121.7mL Atmosphere pressure, Patm (barometer reading) 755 mmtly 755 mmHg | 19.5 m mitg | 21.2 mmtry Vapor pressure of water at lower temperature, Pho(see Appen- dix 6) - 173 -

I am not sure about what they want me to do here?

Answer 1

Trial 1:

1 (a) Pressure of dry air = (755 - 19.8 ) mmHg = 735.2 mmHg

(b) Corrected experimental volume of dry air (low temperature) = 118.4 mL * ( 735.2/ 755) = 115.3 mL

2. V_L = 144.9 mL * ( 295/ 370.8) = 115.28 mL

3. % error = ( 115.28 - 115.3)* 100/ 115.28 % = 0.017 %

4. (a) V_H/ T_H = 144.9/ 370.8 = 0.39

(b) V_DA/ T_L = 115.3/ 295 = 0.39