A diprotic weak base (B) has pKvalues of 4.808 (pK01) and 8.414 (p K12). Calculate the fraction of the weak base in...

Question

Question

$A diprotic weak base (B) has pKvalues of 4.808 (pK01) and 8.414 (p K12). Calculate the fraction of the weak base in each of i$

Answer 1

Answer #1

pKa1 + pKa2 = 14

pKb1 = 4.808 ---------------> pKa2 = 9.192

pKb2 = 8.414--------------------> pKa1 = 5.586

Ka1 = 2.59 x 10^-6

Ka2 = 6.43 x 10^-10

PH = 6.703

[H+] = 1.98 x 10^-7 M

[H+]^2 = 3.93 x10^-14

Ka1 Ka2 = 1.66 x 10^-15

Ka1 [H+] = 5.13 x 10^-13

[H+]^2 + Ka1 Ka2 + Ka1 [H+] = 5.54 x 10^-13

B = Ka1 Ka2 / [H+]^2 + Ka1 Ka2 + Ka1 [H+] = 3.00 x 10^-3

BH+ = Ka1 [H+] / [H+]^2 + Ka1 Ka2 + Ka1 [H+] = 0.926

BH2+ = [H+]^2 / [H+]^2 + Ka1 Ka2 + Ka1 [H+] = 0.0709

Answer 2

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