Question

calculate the mass in grams of BaSo4 that was formed from the following information.

Moles of Ba(OH)2 = Moles BaSo4

volume Ba(OH)2 dispensed = 10 ml

Molarity of H2SO4 used = 0.100 M

Molarity of Ba(OH)2 solution = 0.118 M

Answer 1

_Ba (OH)2 + H2SO4 -> Ba04 + 2H20 Yes, according to balanced_equation + mole of Bacong = mole of B9504 * 1000 Molarity of BacOH)2 & mole of Bacom) 2 Volume of BaCOH)2 (in mij reste mode 01118 M : mole of Ba(OH)2 * 1000 - 10 ml mule of Ba coit), : 0.118. *.10. 1000 mole of Ba(019) 23 0 .00118_mel mole of BacOH),_: Mass of BaCOH), in gram for given mole Molar mass of Ba(OH)2 0.00118 mol Mass of Ba(OH)2 in gram 171.349/mol Mass of Bacon), in gram -0.00118 x 171.34 6.202 gram . gramas Answer