1. Ans :-
Let Volume of HCl solution = V liter
Given that, HCl and HNO3 have equal volume
So,
Volume of HNO3 solution = Volume of HCl solution = V liter
Total volume after mixing the two solutions = VT = V + V = 2V liter
Because,
Normality = gram equivalents of solute/Volume of the solution in L
So,
Gram equivalent of HCl (E1) = Normality x Volume of HCl solution
because, Normality = Molarity x Valency factor
So,
Gram equivalent of HCl (E1) = Molarity x Valency factor of HCl x Volume of solution in L
= 0.10 x 1 x V
= 0.10 V
Similarly,
Gram equivalent of HNO3 (E2) = Normality x Volume of HNO3 solution
because, Normality = Molarity x Valency factor
So,
Gram equivalent of HNO3 (E2) = Molarity x Valency factor of HNO3 x Volume of solution in L
= 0.16 x 1 x V
= 0.16 V
Now,
Resultant Normality (NR) = E1 + E2 / VT
= 0.10 V + 0.16 V / 2 V
= 0.26 V / 2 V
= 0.13
So,
[H+] = 0.13 M
We know,
pH = - log [H+]
= - log 0.13 M
= - ( -0.886)
= 0.886
Hence, pH of the resulting solution = 0.886 |
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