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Eleven resilient modulus observations of a ceramic mixture of type A are measured and found to have a sample average of 18.42

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Answer #1

a) H:01 = 022

    H: 012 > 022

The test statistic F = \frac{s1^2}{s2^2}

                              = (2.77)^2/(2.41)^2

                              = 1.32

At alpha = 0.05, the critical value is F(0.05, 10, 9) = 3.1373

Since the test statistic value is not greater than the critical value, so we should not reject the null hypothesis

At 0.05 significance level, there is not sufficient evidence to support the claim that type A ceramic has larger variability than type B.

b) At 95% confidence level, the critical values are

FL = F(0.975, 10, 9) = 0.2646

FR = F(0.025, 10, 9) = 3.9639

The 90% confidence interval for \frac{\sigma1^2}{\sigma2^2} is

$1? 1 $22 * FR 0 -22 s1 1 -22 * Fy

_ (2.77) 1 (2.4152*3.9639* (2.77) 1 23*2.4152*0.2646

27667 > > ceļE 0 =

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