Question

Fill in the blanks with the appropriate numbers to balance the half reactions and the overall reactions. Note: H,O, OH", H,0 and e" (and CT") are repeated on both sides, obviously some will be 0. 1) MnO, + Cu - MnO, + Cu?" in acidic solution. MnO, + 2 H,0 + OH' + 3 e MnO, + OH,O + 4H+ Oc I Cu + OH,O + OH+ 0 0 - | Cu? + OH,O + OH' + 20 3 Cu + 2 MnO, + 4H,0 + OH - 3 Cu + Mno, + OH,0 + 8H 2) Fe? + H,O, - Fe + H20 in acidic solution __Fe? + _H,0 +_H' +_ - _Fe +_H,0 + - HBO, + HẠO + H+ + = - HO + H + F c + . Fe?' +_H,0, +_HO +_ -_Fe" +_HO + H 3) C0,- + Cr. - _C0, +_ H,0 +_ CrẠO, + HgO + C + Co, in acidic solution H' +_e co, + H+ + e - Cr" + HO + HBO + - H+ H + e e Co? + CrO4 + H2O + H - CO, + Cr + H2 + H 4) NO, + Fe(OH), NO," + Fe(OH), in basic solution NO; + __H,0 +_OH +_ -_NO," + H,0 +_OH + OH), +_H2O + OH + e- Fe(OH), + HO + OH + Fe(OH), + H2O + OH - Fe(OH), + NO + H2O + OH

Answer 1

Ansta): fet + H2O2 fets & Ho in cucidic solution & a fe to h2o tort to é 2 fet 3 +04₃0 +04+2e → 2 H2O2 to H₂O + 2H+ + 2ē 2H20 tohto é 2 feet + I H202 + 0 H2O +24+ 2 fets +2420 tort Ans (3) - 3 C₂02 + H2O + oHt to é 6CO2 + H2O + oH+ +6ē - 1 c2207²- + oH2O + 14 H7 + 6€ → 2083 + + I 420toit toe 3 C202 + Ich 07²- + oH₂O + 14 H+ 6CO2 + 2 0834 + 7 K2O toret And (4) No2 e folo4) NO3 + feloH)2 . in basic soin & I No2 + oH2O + 204 to é 1 NO3 + 1H20 toontze & I fecon) + I H20 trore t ze felona + H2O +2016+ oë I NO2 + I fecond t J H2O + 204 trê I NO3 + 1 felOH)2 + IH2O + 2016 +2e