Question

Part 2. Random Variables 4. Two independent random variables Xand y are given with their distribution laws 0.3 0.7 0.8 0.2 Pi

0 0
Add a comment Improve this question Transcribed image text
Answer #1

4) The distribution of the random variable V=3XY is found as

P( V = 0) = P(X = 0) = 0.3 P(V = 12) = P(X = 4, Y 1) = P(X = 4)P(Y = 1) = 0.7(0.8) 0.56 P(V = 24) = P(X = 4, Y = 2) = P(X = 4

Thus the distribution of V=3XY is

V=3XY 0 12 24
P(V) 0.3 0.56 0.14 1.0

Now,

E(V) = 0(0.3) + 12(0.56) + 24(0.14) E(V) = 10.08 E(V2)-0(0.3)122(0.56) 242(0.14) E(V2) -161.28

The variance of the random variable is

Var(V)-E(V)- E(V) Var(V) 161.28-10.082 Var(V)59.6736

We are required to solve only one question. Please post the remaining questions as another post.

Add a comment
Know the answer?
Add Answer to:
Part 2. Random Variables 4. Two independent random variables Xand y are given with their distribution laws 0.3 0.7 0.8...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT