Initial concentration of CO2 = moles / volume = 2 / 5 = 0.4 M
Setting up anICE table with fraction x of CO2 reacted at equilibrium, we have:
2 CO2 2 CO + O2
initial conc: 0.4 0 0
Equilibrium conc: 0.4(1 - 2x) 0.8x 0.4x
Setting up the equation for K, we get: K = [CO]2 * [O2] / [CO2]2
Substituting the value of k and table values:
2 * 10-6 = (0.8x)2 * 0.4x / (0.4(1 - 2x))2
Solving, we get: x = 0.01
[CO2] = 0.4 * (1 - 2 * 0.01) = 0.392 M
[CO] = 0.8 * 0.01 = 0.008 M
{O2} = 0.4 * 0.01 = 0.004 M
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