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methor eter, r 1 13 Vocz ANP 151 Exam 2 Version W (2002(g) 209(9) + O2(g) Ks = 2.00x 10 If 2.0 mol CO2 is initially placed in
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Answer #1

Initial concentration of CO2 = moles / volume = 2 / 5 = 0.4 M

Setting up anICE table with fraction x of CO2 reacted at equilibrium, we have:

         2 CO2    \rightarrow                   2 CO        +          O2

initial conc:               0.4                                         0                          0

Equilibrium conc: 0.4(1 - 2x)                            0.8x                       0.4x

Setting up the equation for K, we get: K = [CO]2 * [O2] / [CO2]2

Substituting the value of k and table values:

2 * 10-6 = (0.8x)2 * 0.4x / (0.4(1 - 2x))2

Solving, we get:   x = 0.01

[CO2] = 0.4 * (1 - 2 * 0.01) = 0.392 M

[CO] = 0.8 * 0.01 = 0.008 M

{O2} = 0.4 * 0.01 = 0.004 M                     

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