1st find the energy of blue light
Given:
lambda = 465 nm = 4.65*10^-7 m
Find energy of 1 photon first
use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(4.65*10^-7 m)
= 4.275*10^-19 J
This is energy of 1 photon
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 4.275*10^-19*6.022*10^23 J/mol
= 2.574*10^5 J/mol
= 257.4 KJ/mol
This energy is greater than bond dissociation energies of Cl2 and F2
Answer: F2 and Cl2
Question 3 1 pts Given the bond dissociation energies (in kJ/mol) for the following diatomic molecules Cl2 (243), F2 (1...
Part A. Given the bond dissociation energies (in kJ/mol) for the following diatomic molecules Cl2 (243), F2 (158), H2 (436), O2 (498), N2 (945) choose the one(s) that could be broken by using blue light (λ=465 nm). Part B. Given the bond energies (in kJ/mol) of the following bonds: F–F (155), F–Cl (193), and Cl–Cl (243), estimate the molar enthalpy of formation of ClF(g), that is find ∆H for the following reaction ½Cl2(g) + ½F2(g) → ClF(g)
Bond Dissociation Energies (for A-B Bond broken AH, kJ/mol Bond broken → A A4, kJ/mol + B) Bond broken mo H-H CH3CH2CH2-H (CH3)2CH-H (CH3)3C-H 436 423 413 400. H-Br 366 CH3CH2CH2-Br 294 (CH3)2CH-Br 298 (CH3)3C-Br292 Br-Br 193 H-CI 432 CH3CH2CH2-CI 354 (CH3)2CH-CI 355 (CH3)3C-CI 349 CI-CI 243 Alkane halogenation is a two-step reaction, as shown below. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. Step 1: Number CH3CHCH3...
Given the following: O2 (g) + 2F2 (g)------> 2OF2 (g) delta H=+24.5 kJ/mol Bond dissociation energies: F2= 159 kJ/mol; O2 (double bond) = 498 kJ/mol Calculate the bond strength of the O-F bonds in OF2.
8. Given the following bond dissociation energies, what is the AF" for the formation of hydrogen chloride? H2(g) + Cl2(g) → 2 HCI(g) Bond Energy (kJ/mol) Bond 436 243 432 H-H Cl-CI H-Cl A) 185 kJ/mol. B) -92.5 k.J/mol. C) 92.5 kJ/mol. D) -185 kJ/mol.? E) 277.5 kJ/mol.
Bond strength decreases dramatically in the diatomic molecules from N2 (942 kJ mol-1) to O2 (495 kJ mol-1) to F2 (155 kJ mol-1). What accounts for this behavior?
1. Bond Dissociation Energies and Free Radicals Bond Bond Dissociation Energies (kJ/mol) Bond BDE Bond BDE (kJ/mol) (kJ/mol) H-H 436 CH3-H 439 H-F 570 CH3CH2-H 432 H-CI 432 (CH3CH2 413 BDE Bond (kJ/mol) 10-N 350 0-0 180 F-F O-H 0-C O-F 460 BDE (kJ/mol) | 200 180 159 | H-Br H-I 366 298 404 350 O-C1200 O-Br (CH3)3C-H C-C (sigma) C=C(pi) 210 C1-C1243 Br-Br 193 243 0 -I 220 I-I | 151 A. The enzyme methane monooxygenase catalyzes a remarkably...
Table 1: Bond Onders and Bond Energies for Selected Molecules Bond Bond Molecule Lewis Structure Bond Energy Order (kJ/mol HF H-8: H-F 1 570 HCI H-C: H-C1 11 432 HBr H-Br 366 НІ H-I 298 Cl2 C1-C1 1 Br-Br I-I 151 H2 Η-Η H-H 436 HO :0-H O-H REF 243 193 B12 498 н HH I H-C-C- H3CCH3 H C-C C-H 376 420 HH HH HCCH C-C C-H 720 444 H-C=C-H CO2 C-O 804 H-C-H H.CO C-O C-H 782 364...
Question 2 4 pts Use the given average bond dissociation energies (BDE) to estimate A Hreaction for the combustion of hydrogen in oxygen that produces water: 2H2 (8) + O26 --> 2H20 (6) Bond BDE(kJ/mol) H-H 436 0-0 498 H-O 460
Given the bond energies (in kJ/mol) of the following bonds: F–F (155), F–Cl (193), and Cl–Cl (243), estimate the molar enthalpy of formation of ClF(g), that is find ∆H for the following reaction ½Cl2(g) + ½F2(g) → ClF(g) A. 209 kJ/mol B. -50. kJ/mol C. –8 kJ/mol D. –209 kJ/mol E. 8 kJ/mol
Which of the following statements are FALSE, given the following bond dissociation energies? Assume that bond energies accurately determine heats of reaction. Check all that are false. BE[H-H] = 436 kJ/mol BE[H-N] = 393 kJ/mol BE[H-O] = 460 kJ/mol BE[O=O] = 499 kJ/mol 1. NH(g) + H2(g) ---> NH2(g) + H(g) is an exothermic reaction. 2.ΔH°f[H(g)] = 218 kJ/mol 3. ΔH°[H2O(g) ---> 2 H(g) + O(g)] = 920 kJ/mol 4. An H-H bond is stronger than an H-O bond. 5....