heat of formation is the heat released or absorbed (enthalpy change) during the formation of a pure substance from its elements at constant pressure (in their standard states).
Standard state for hydrogen and oxygen is gaseous state and sulfur is solid state.
Review Problem 6.090 Which of the following thermochemical equations can have AH for the heat of the reaction? a) N...
Review Problem 6.086 Given the following thermochemical equations, 2Cu + S(s) - Cu2S(s) AH° = -79.5 kJ S(s) + O2(g) → SO2(9) AH = -297 kJ Cu2S(s) + 202(g) → 2CụO(s) + SO2(g) AH° = -527.5 kJ calculate the standard enthalpy of formation (in kilojoules per mole) of Cuo(s). AH°(Cuo(s)) - kJ/mol The number of significant digits is set to 3; the tolerance is +/-2% Show Work is REQUIRED for this question: Open Show Work Review Problem 6.087 Given the...
3. Use the thermochemical equations shown below to determine the enthalpy for the reaction for CH3COOH()2C(s) +2H2(g) + O2(g) 2CO2(g)+ 2H2OI)CH3COOH(l) + 202(B) AH 3484 kJ C(s)+ O2(g)CO2(g) AH= -1576 kJ AH= -2288 kJ 2H2O(I) 2H2(g)+ O2(g)
2. Use the thermochemical equations shown below to determine the enthalpy for the reaction: (5 marks) C3H8(0) + 5O2(g) →3CO2 + 4 H2O) CO2 +Cgraphite) + O2 AH° = 221.6KJ H2(g) + 1/2O2(g) +H2O AH = -160.3KJ 3 C(graphite) + 4H2(g) →C3H8(9) AH = -58.5KJ 3. Use the thermochemical equations shown below to determine the enthalpy for the reaction: (5 marks) SO2(g) →S(8) + O2(9) H2S(g) + 3/202(g) → H2SO3(1) H2SO3(1)→ H2O +SO2(g) H2S(9)+ 1/2O2(0)+S(8) + H2O) AH = -306KJ...
Calculate the value of AH° for the reaction 2 C2H2 () + 502 () 4002) + 2 H20 (1) given the following thermochemical equations: AH° = - 242 kJ AH° = - 394 kJ H2(g) + 4202) → H20 (8) C(s) + O2(%) + CO2(8) 2 C(s) + H2(g) → C2H2 (6) H20 () → H30Ⓡ AH° = +227 kJ AH° = +44 kJ TO - 907 kJ 0 - 2602 kJ 0 - 2514 kJ - 1694 kJ
Calculate AH for the following reaction, CaO(s) + CO2(g) CaCO3(s) given the thermochemical equations below. 2 Ca(s) + O2(g) + 2 Cao(s) AH = -1270.2 kJ C(s) + O2(g) CO2(g) AH = -393.5 kJ 2 Ca(s) + 2 C(s) + 3 O2(g) → 2 CaCO3(s) AH = -2413.8 kJ 0-750.1 kJ O +350.2 kJ 0 -178.3 kJ O +2870.6 kJ
45. The following thermochemical equations can be written for the oxides of iron: Fe (s)+2 O2 (g)- FeO (s) 3Fe (s)+ 202 (g) Fe,O4 (s) 0.00 AH° -272.0 kJ AHo= -1118.4 kJ НОЛИ С 02 20p Find AH° for 4FeO (s) sl uoy tr bomol od liw stiue uibo to anurg youwo Fe (s) + Fe3O4 (s ) uOv bns obizobd muibe o 1.6PL! VAofom HODW HOOWTO o.com
a) H2SO4(l) b) CaSo4*2H20 c) Na2SO4(s) Review Problem 6.091 Enter the thermochemical equations, including values of AH° in kilojoules per mole (from the table below) for the formation of each of the following compounds from their elements, with everything in standard states. Include physical states in your answer. Use minimal integer numbers for coefficient input. Standard Enthalpies of Formation of Typical Substances AH (KI mot-1) AHi(I mol-1) AH (KJ mot-1) AH (KI mol-) Substance Substance Substance Substance NO(g) 90.37 Ag)...
Review Problem 6.083 Calculate AHo in kilojoules for the following reaction, the preparation of the unstable nitrous acid, HNO2 HNO2 ) + NaCl) Ha)+NaNO2G) Use the following thermochemical equations: 1) 2NaCl) +HO)2HCI(g)+ NayO) AH= +507.31 kJ 2) NO(g)+NOg) + Na,O)+ 2NaNO,() AH"=-427.14 k 3) NO(g)+NO() NO(g) +O;e) AH*=-42.68 k 4) 2HNO,() N;O(g) + O;(g) + H2O(D AH +34.35 kl AH= kJ The number of significant digits is set to 4; the tolerance is +/-2 % Show Work is REQUIRED for...
Review Problem 6.085 Given the following thermochemical equations, COG) + Cl2(g)—COClz0) H,0() + COC126) + 2NaBr(s) — 2NaCIG) + Ca(OH)2C) + Brz(1) Ca(OH),() — COC) + H20() calculate the value of AH° (in kilojoules) for the reaction Cl:(8)+NaBr(s) — NaCl(s) + Brz() AH'= -110.9 kJ AH° = -60.2 kJ AH° = +65.1 kJ AH = The number of significant digits is set to 3; the tolerance is +/-2% Show Work is REQUIRED for this question: Open Show Work
Which of the processes represented by the following chemical equations are exothermic?Choose one or more:A. $$heat+CaO(s)+3C(s)→CaC2(s)+CO(g)B. $$CH4(g)+2O2(g)→CO2(g)+2H2O(g)+heatC. $$CH3OH(g)+32O2(g)→CO2(g)+2H2O(g) ΔH=−676kJ/molD. $$2H2O(g)→2H2(g)+O2(g) ΔH=+483.6kJ/molE. $$I2(s)→I2(g)F. $$H2O(g)→H2O(l)