Question

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1. Naturally occurring iodine has atomic mass of 126.9045 amu. A 12.3849 gram sample of iodine is accidentally contaminated with an additional 1.0070 grams of 129 I, a synthetic isotope used to treat diseases of the thyroid. The mass of Iodine 129 is 128.9050 amu. Find the apparent “atomic mass” of the contaminated iodine. (Show the math for this.)

2. The mass of the average blueberry is 0.75 grams and the mass of an automobile is 2.0 X 10 3kg. Find the number of automobiles whose total mass is the same as 1 mole of blueberries. (Show all math with units. )

Answer 1

1. Sample contains 12. 3849g 128 g with 1.00070 g 1291 Fraction of each isotope : 12 = 12:3849 g 0.925241 - 2 I 1 12.3849 g +1000070g 1277 + 2 I 1291 - 16000709 - - 0.074759_ 12 3849 g +1.00070 g Apparent atomic mass = fraction 21) (mass 1271) + fraction all I) (mass 1291) - - (0.92524)) (136-9045 amu)+(0.0747594)(128-9050 amu) = 117.4172 amu + 9.636 9 amu = 127.054 1 amu

2 1 mol blueberries = 6.022 X 1023 blueberries Mass of 1 mol blueberries of mol bleckerry X 6.022 x 1023 blueberry x 0. 75 g o Imol blueberry I blueberry = 4.5165 X 1028 9 Number of automobiles = mass of blueberries Cal Mass of an automobile - 405165 X10289 y = 203 x 1017 - 2.08 10² x 103 g - Number of automobiles with same total mass as 1 mole of blueberries : 203 X 1017
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