Given,
= 11 , = 0.3
We convert this to standard normal as
P(X < x) = P(Z < x - / )
So,
P(10.9 - 0.2 < < 10.9 + 0.2) = P( < 10.9+0.2) - P( < 10.9 - 0.2)
= P( < 11.1) - P( < 10.7)
= P(Z < (11.1 - 11) / 0.3) - P(Z < (10.7 - 11) / 0.3 )
= P(Z < 0.33) - P(Z < -1)
= 0.6293 - 0.1587
= 0.4706
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