Question

After creating her standard curve for absorption versus the concentration (M) of FD&C Red 40, a student found that her best fit linear line for FD&C Red 40 was y = 2,840x + 0.005.

Her Kool-Aid sample had an absorbance of 0.635. If 0.546 grams of Kool-Aid powder was used to prepare an 8-fl oz cup of her assigned flavor, what is the percent by mass of FD&C Red 40 in her 8-fl oz cup?

Answer 1

Given 2,840x +0.005 Her kool- Aid Sample had an absorbance of 0.635. zł 0.546 grams of kool-Aid powder was used to prepare an o-floz cup of her assigned flavors - the concentration of Red H0 by means of the Equation of the clear line is Y = 2,840x + 0.005 => 2,840 X = 1 +0.005 X = Y+ 0.005 2,840 x = 0.635 +0.005 2,840 - x = 0.64 2,840 X = 2:25 x10-41 molle

The grams of red to present g= mv mm = (21258184 fill) (8 7) (15Simps) = 12:25x104moll) (802)(2.958005) (496-423) = 2:63x10-59 ... The grams of sed 40 present = 0.0269 The percentage of red your % Red 40 = 19*100)/ g sample - (0.026) (109) 0.546g = 2.6 0.5469 = 4,76% of red 40 = 4.76%