2 SO2 + O2. --->. 2 SO3
Answer - 2,1,2
First balance O atom by multiply 2 to SO3 . So total oxygen = 6
Now multiply 2 to SO2 and reaction will be automatic balance .
Question 1 (2 points) Saved Which set of coefficients balances the equation SO2 + O2 + SO3? 2, 1, 1 O 2, 1, 2 O 4,...
QUESTION 17 1 points [CLO-4] Consider the following equilibrium. 2 SO2(g) + O2 (g) ==== 2 SO3 (8) The equilibrium cannot be established when container [Hint: no need to do any calculations !!! 1.0 mol SO3 (8) is/are placed in a 1.0-L 0.25 mol of SO2 (g) and 0.25 mol of 503 (g) 0.50 mol O2(g) and 0.50 mol SO3 (g) 0.25 mol SO2 (g) and 0.25 mol O2 (g) 0.75 mol SO2 (9)
5. For the reaction... SO2 + O2 <=> SO3 If the equilibrium position shifts to the right, the concentration of O2 will (2 points) o remain constant increase Decrease
The reaction 2 SO2 + O2 = 2 SO3 is exothermic. Which of the following would be true for a person wanting to force the equilibrium to the right? a. They should (increase/decrease) the reaction temperature b. They should (increase/decrease) the total pressure c. they should (add/remove) SO2 d. they should (add/remove) O2 e. they should (add/remove) SO3 why?
1.For the reaction at equilibrium 2 SO3↔ 2 SO2 + O2 (∆Horxn= 198 kJ/mol), if we increase the reaction temperature, the equilibrium will (1 point ) * No shift None of the above Question lacks sufficient information Shift to the right 2. For the equilibrium reaction 2 SO2(g) + O2(g) ↔ 2 SO3(g), ∆Horxn = -198 kJ/mol. Which one of these factors would cause the equilibrium constant to increase? (1 point ) * Add a catalyst Decrease the temperature None...
Calculate Δ G for the reaction 2 SO2 (g) + O2 (g) → 2 SO3 (g) when P of SO2 = 0.500 atm, P of O2 = 0.0100 atm, and P of SO3 = 0.100 atm. The value for Δ G^o for this reaction at 298 K is -141.6 kJ. ΔG = ???? kJ I got -160.9 kj but it is incorrect.
Calculate AG for the reaction 2 SO2 (g) + O2 (g) → 2 SO3 (g) when P of SO2 = 0.500 atm, P of O2 = 0.0100 atm, and P of SO3 = 0.100 atm. The value for AGº for this reaction at 298 K is -141.6 kJ. AG= O * kJ Is this reaction spontaneous or non-spontaneous under these conditions? Spontaneous or non-spontaneous? spontaneous
QUESTION 21 1 point ==== [CLO-4] Consider the following equilibrium. 2 SO2 (g) + O2 (g) 2 S03 (g) The equilibrium cannot be established when [Hint: no need to do any calculations !!!) 1.0 mol SO3 (g) is/are placed in a 1.0-L container 0.75 mol SO2 (g) 0.25 mol SO2 (g) and 0.25 mol O2 (g) 0.50 mol O2 (g) and 0.50 mol SO3(g) 0.25 mol of SO2 (g) and 0.25 mol of SO3(g) Save All Answers Click Save and...
Consider the reaction: 2 SO2 (g) + O2 (g) → 2 SO3 (9) If 278.2 mL of SO2 is allowed to react with 168.1 mL of Oz (both measured at STP), what is the theoretical yield o SO3? V AUD S moo? A W Theoretical Yield mol If 180.7 mL of SO3 is collected (measured at STP), what is the percent yield for the reaction? 190 AM OO ? Percent Yield =
Given the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g) Starting with 0.100 M of SO2 and 0.050 M of O2, which value of K should be used and why? a. KC because the chemicals are in the gas phase. b. KP because the concentrations are in Molarity. c. KP because the chemicals are in the gas phase. d. KC because the concentrations are in Molarity.
1).From the following enthalpy changes, S (s) +3/2 O2 (g) 2 SO2 (g) SO3 (g) O2 (g)2 SO3 (g) AH =-395.2 kJ AHo 198.2 kJ Calculate the value of AHo for the reaction by using Hess's law of Heat Summation S(s) O2 (g) SO2 (g) 2) Oxyacetylene torches are fueled by the combustion of acetylene, C2H2. 4 CO2 (g) +2 H20 (g) 2 C2H2 + 5 O2 (g) If the enthalpy change for the reaction is -2511.14 kJ/mol, a) How...