Question

Part B: Short Answer and Problem Solving Questions Show your work for all calculation problems. Report your answer with corre
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Here , tos of heat by de) (Gain of heat by to) - MC AT = mc AT -(10.0) (0.902) (4-343 ) = (40)(4.184) T4 -298) -9.02 ( 4 - 3+thank you vmuch...

Add a comment
Know the answer?
Add Answer to:
Part B: Short Answer and Problem Solving Questions Show your work for all calculation problems. Report your answer...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • please show work? Question 34 (8 points) A 50.0 g sample of H20 at 100.00°C was...

    please show work? Question 34 (8 points) A 50.0 g sample of H20 at 100.00°C was placed in an insulated cup. Then 25.3 g of a metal at 25.00°C was added to the water. The temperature of the water dropped to 96.68°C. What is the specific heat of the metal in J/g°C? The specific heat of water is 4.184 J/g°C. Assume that the heat absorbed by the cup is negligible. Please report your answer to the correct number of significant...

  • 4. Heat transfer: q = mass x Cs x ΔT and –qreaction = +qsolution a. A...

    4. Heat transfer: q = mass x Cs x ΔT and –qreaction = +qsolution a. A piece of metal with a mass of 8.6 g was heated to 100.0°C and dropped into a coffee cup calorimeter containing 402.4 g of water at 25.0°C. If the temperature of the water and the metal at thermal equilibrium is 26.4°C, what is the specific heat of this metal in J/g°C? b. How much heat energy must be added in order to boil a...

  • please help me. Thanks A piece of copper metal weighing 36.3 g is initially at 100.0...

    please help me. Thanks A piece of copper metal weighing 36.3 g is initially at 100.0 degree C. It is dropped into a coffee cup calorimeter containing 50.0 g of water at a temperature of 20.0 degree C. After stirring, the final temperature of both copper and water is 25.0 degree C. Assuming no heat losses, an that the specific heat capacity of water is 4.184 J/g degreeC, what is the specific heat capacity of the copper in J/g degreeC?

  • I know the answers but I don't know how to solve the work. Please show the...

    I know the answers but I don't know how to solve the work. Please show the work 1.) Answer: D 2.) Answer: D 3.) Answer: A Aluminum has a specific heat of 0.902 J/g.°C. How many joules of heat are required to change the temperature of 8.50 grams of aluminum from 25.0°C to 93.4°C? a. 7.67 J b. 71.7 J c. 192J d. 524 J Water has a specific heat of 4.18 J/g. °C. If 35.0 g of water at...

  • What is the heat of a reaction with a total reaction mixture volume of 70 5...

    What is the heat of a reaction with a total reaction mixture volume of 70 5 mL if the reaction causes a temperature change of 6.4 °C in a calorimeter? Assume that the reaction mixture has a density of 1.00 p/ml. and a specific heat of 4.184 JigC The calorimeter has a heat capacity of 10.0 JC Answer What is the heat, q, in youles transfered by a chemcal reaction to the reservoir of a calorimeter containing 95.0g of dilute...

  • please write clearly and use significant figures. thanks in advance 3. Calculate the heat absorbed by...

    please write clearly and use significant figures. thanks in advance 3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0°C. The specific heat of water is 4.18 J/gºC. Show your work Final Answer 4. Aluminum metal has a specific heat of 0.901 J/gºC. How much heat is transferred to a 6.75 g piece of aluminum initially at room temperature, 20.0°C, when it is placed into boiling water? The temperature of boiling...

  • If a 105 g piece of aluminum (specific heat 216 cal/g°C) at 25.0°C absorbs 542 cal,...

    If a 105 g piece of aluminum (specific heat 216 cal/g°C) at 25.0°C absorbs 542 cal, what will its new temperature be? Use the correct number of significant figures. f 10.0 g of NH NO, added to 50.0 mL of water cause a 14.3°C decrease in temperature, what is the heat of solution for ammonium nitrate per gram? (Assume the specific heat for the solution is 4.184 J/g °C.)

  • please please answer all question 17. How many JOULES of energy are needed to warm 4.37...

    please please answer all question 17. How many JOULES of energy are needed to warm 4.37 g of silver (Ag) from 25.0 c to 27.5 C? The specific heat of silver is 0.24c a. 0.14J b. 2.6 c. 46 J d. 0.022 18. Given the table below of specific heat capacities, which one will experience the SMALLEST increase in temperature if 10.0 J of heat is added to 1.00 g of each of these substances? Water Cast iron Lead (Pb)...

  • CHM 2045L- Heat Effects and Calorimetry Post-Lab Sheet: Heat Effects and Calorimetry Name: Show calculations for...

    CHM 2045L- Heat Effects and Calorimetry Post-Lab Sheet: Heat Effects and Calorimetry Name: Show calculations for credit. Be mindful of significant figures. 1. A piece of aluminum with a mass of 32.5 g is heated to 674°C and put into a Syru foam calonnea containing 582 g of water that is initially at 212℃ Assuming no heat is lost, what is the final temperature? The specific heat of aluminum is 0.902 J/g'C; for water 4.18 J/gC. (6 pt.)

  • A 25.00 gram sample of an unknown metal initially at 99.0 degrees Celcius is added to...

    A 25.00 gram sample of an unknown metal initially at 99.0 degrees Celcius is added to 50.00 grams of water initially at 9.47 degrees Celcius. The final temperature of the system is 20.15 degrees Celcius. Calculate the specific heat of the metal. (The specific heat of water is 4.184 J/g*C). Record your answer in scientific notation using three significant figures.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT