Hello, my question is actually in regards to risk management insurance . Here is the questions I need assistance with.
3. Sol:
There are a total of 4 possible cases:
Both A and B are lost, in which case total loss is $14000.
A is received but B is lost, in which case total loss is $6000.
B is received but A is lost, in which case total loss is $8000.
Both A and B are received, in which case total loss is $0.
Since delivery of A is independent of delivery of B, keeping this in mind the probability values are calculated as shown below:
Let L denote the total loss.
P(L=14000) = 0.05*0.25 = 0.0125
P(L=6060) = 0.95*0.25 = 0.2375
P(L=8000) = 0.05*0.96 = 0.048
P(L=0) = 0.95*0.96 = 0.912
The expected value of dollar amount loss is:
E(L) = 14000*0.05 + 8000*0.20 + 60000*0.15 + 0*0.60 = $3200
Var(L) = 140002*0.05 + 80002*0.20 + 60002*0.15 + 02*0.60 - (3200)2 =17760000$2
Thus the variance has been correclty calculated. The units are dollar squared.
Hello, my question is actually in regards to risk management insurance . Here is the questions I need assistance with....
Hello this questions is in regards ti risk management
insurance.
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