Question

when 18.0a oe methane and enough O2(4) is heatar and Converted au methane nto Cola) and tz0-What are the male fraction of each gasif the total pressure of gasses is 1.50 atm? CHlg)+0-g) C0G}+ H26)

Answer 1

The balance combustion reaction of complete combustion of methane is as follows: CH.(g) +20,(g)-A CO(g) + 2 H2O(g) Reactants Products Number of moles = amount in g/molar mass Number of CH4 : 18.0 g/ 16.04 g/ mole = 1.12 mole CH4 Calculate the mole sof CO2 and H2O as follows: Moles of CO2 = 1.12 mole CH4 *1 mole CO2/ 1 mole CH4 1.12 mole CO2 Mole of H20= 1.12 mole CH4 * 2 mole H201.00 mole CH4 =2.24 Mole H2O Total moles after reaction = 1.12 +2.24 = 3.36 moles Mole fraction of CO2 = moles of CO2 / Total moles = 1.12/3.36 = 0.33 Mole fraction of H20= moles of H20 / Total moles = 2.24/3.36 = 0.67