Please Calculate the theoretical yield and the percent yield of this aldol reaction.
Unknown ketone: cyclohexanone
Unknown aldehyde: p-Anisaldehyde
Actual yield: 0.067
Our aldol mixture was our unknown ketone (0.002 mol) with 4.0 mL of 95% ethanol in a 25 mL Erlenmeyer flask. And we added our unknown aldehyde (0.008 mol) and 3.0 mL of 1 M NaOH.
Please Calculate the theoretical yield and the percent yield of this aldol reaction. Unknown ketone: cyclohexanone Unkno...
what is the theoretical yield and what is the percent yield? In a 125-mL Erlenmeyer flask containing a magnetic stirring bar, mix 0.05 md benzaldehyde with the theoretical quantity of acetone, and add one-half the ture to a solution of 5 g of sodium hydroxide dissolved in 50 mL of water and 40 mL of ethanol at room temperature (<25°C). After 15 minutes of stirring ada remainder of the aldehyde-ketone mixture and rinse the container with a little ethanol to...
what is the theoretical yield of anisalacetophenone and dibenzalacetone formed? thank you. The Aldol Condensation Precautions: Acetone, ethanol and acetophenone are flammable; work in a fume hood. Sodium hydroxide is a strong base and can cause severe skin burns and eye damage. Safety goggles are required. Gloves are recommended. Purpose To carry out two Aldol condensation reactions in which no heat is needed to obtain the condensation product. The two reactions differ in the number of enolizable protons at the...
Please refer to the Aldol Condensation experiment in your lab manual (page 89) • Calculate the amounts of all chemicals needed in measurable amounts (i.e. grams or milliliters rather than moles.) • Determine the theoretical yield for the reaction. Mixture A: Prepare a solution of 5g of sodium hydroxide dissolved in Du and 40ml of ethanol at room temperature in a 250 ml Erlenmeyer flask. Mixture B: Mix 5.1 ml(5.31 g) of benzaldehyde (MW 106 g/mol; d = 1.04 g/ml)...
R1= OCH2C6H5, R2= OCH3 Identify the limiting reagent and calculate the theoretical yield? NaOH H3C -H20 R2 R1 Procedure: 1. Prepare a water bath for use later in the experiment by filling a pyrex dish -half full of water and heating it to 70 °C on a stirrer/hot plate. 2. Combine 3.5 mmol of your aldehyde and 3.5 mmol of your ketone with 2 mL of 95% ethanol in a 25- mL round-bottom flask and swirl the mixture briefly. 3....
Organic Chemistry 2 Experimental Outline In its simplest form, the aldol condensation is a self-addition involving two molecules of the same aldehyde or ketone, in the presence of a base, and results in the formation of a new carbon-carbon bond joining the carbonyl carbon of one molecule to the a-position of the second. In many cases - if the reaction conditions aren't sufficiently mild - the initially formed aldol product reacts further in an elimination reaction to give what is...
Aldehyde: ZPA Ketone: BCK Amount of material started with: 2 mL of aldehyde and 0.5 mL of Ketone Recrystallized Mass: 1.53 g Melting Range: 196-200 C Recrystallization Solvent: 9:1 Ethanol/Acetone 1) structure of product 2)theoretical yield 3)isolated and percent yield 6.1724 7.6069 7.5891 Z-8, CDC13 Z-B, CDC13 7.2839 2724 7.6069 7.5891 4.061 7.0012 6.9836 7.2839 7.2 6.08.18 8862 7.0 4.0666 7.0012 6.9836 3.9987 -3.1154 Ippm] Ippm] component. The possible aldehydes are benzaldehyde, 4-methylbenzaldehyde (p-tolualdehyde), 4-methoxybenzaldehyde (p-anisaldehyde), and E-3-phenyl-2-propenal (cinnamaldehyde). The...
S Ketone Aldehyde 9. Based upon the procedure given below, answer the following questions about the aldol condensation reaction: "In a clean 50 mL Erlenmeyer flask, add the ketone (0.5 g), aldehyde (2.0 mL), 95 % ethanol (10 mL) and 2 M aqueous sodium hydroxi de." Assume the aldehyde and ketone are the answers you provided in Question 8. a. Determine the limiting reagent for the above reaction. Only perform calculations on the organic reactants. Write out all calculations to...
2. Calculate the limiting reagent, theoretical yield, and percent yield of the following reaction. (6 pts) o= NaOH/H20 5.2 g MW: 106.12 g/mol H3C CH3 1.3 g MW: 58.08 g/mol 3.0 g MW: 234 g/mol
2. Calculate the limiting reagent, theoretical yield, and percent yield of the following reaction. (6 pts) NAOH / H20 2 CHз Нас 3.0 g 1.3 g 5.2 g MW: 234 g/mol MW: 58.08 g/mol MW: 106.12 g/mol
2. Calculate the limiting reagent, theoretical vield. and percent yield of the following reaction. (6 pts) NaOH / H20 H + 5.2 g MW: 106.12 g/mol H3C CH3 1.3 g MW: 58.08 g/mol 3.0 g MW: 234 g/mol