Question

Answer the following question.

B Putting It Together: Which Procedure Do I Use? X9.3.17 O of 1 Point EQuestion Help In a survey of 1015 adults, a polling agency asked, "When you retire, do you think you will have enough money to live comfortably or not. Of the 1015 surveyed, 535 stated that they were worried about having enough money to live comfortably in retirement. Construct a 90% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2) Click here to view the table of critical t-values Click here to view the table of critical values of the chi-square distribution. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to three decimal places as needed.) OA. There is 90% confidence that the true proportion of worried adults is between and B. There is a 90% probability that the true proportion of worried adults is between and O C. 90% of the population lies in the interval between and Click to select and enter your answer(s) and then click Check Answer. Check Answer Clear All All parts showing

Answer 1

sample proportion, = 0.5271
sample size, n = 1015
Standard error, SE = sqrt(pcap * (1 - pcap)/n)
SE = sqrt(0.5271 * (1 - 0.5271)/1015) = 0.0157

Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, Zc = Z(α/2) = 1.64

CI (Proportion) = (o-z-p60, P), p+zay/B1, @)

Margin of Error, ME = zc * SE
ME = 1.64 * 0.0157
ME = 0.0257

CI = (pcap - z*SE, pcap + z*SE)
CI = (0.5271 - 1.64 * 0.0157 , 0.5271 + 1.64 * 0.0157)
CI = (0.5014 , 0.5528)

There is 90% confidence that the true proportion of worried ADULTS IS BETWEEN 0.5014 AND 0.5528